In(e^2x)=19/5 - solution

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Solution for In(e^2x)=19/5 equation:

1*x^4-(2*x^2)+0*x^3+0*x-8 = 0

44;48;15;18;0;0

5;6;1;9;2;1

1;15;1;10;2;0

sin(x)-cos(x)-0.2;(sin(x))^3-(cos(x))^3-y

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